Module 5 • Earth Fault Loop Impedance & Fault Current
Prospective Fault Current Calculation
<h2>What is prospective fault current?</h2> <p>Prospective fault current (PFC) is the maximum current that would flow under fault conditions. It must be calculated to verify that protective devices have adequate breaking capacity — a device that cannot interrupt fault current may explode, causing fire or injury.</p> <h2>PFC at the origin</h2> <div style="background:var(--pill-bg);padding:16px;border-radius:10px;margin:12px 0;font-family:monospace;font-size:16px"> PFC = Uo / Ze </div> <p>Where Uo = nominal line-to-earth voltage (230V) and Ze = external earth fault loop impedance.</p> <h2>Worked example</h2> <p>Ze measured at origin = 0.28Ω</p> <p>PFC = 230 / 0.28 = <strong>821A</strong></p> <p>The MCB or fuse at the origin must have a rated breaking capacity (Icc) of at least 821A. Standard domestic MCBs are rated 6kA — more than sufficient.</p> <h2>Short circuit current between line and neutral</h2> <p>For a bolted short circuit between line and neutral:</p> <div style="background:var(--pill-bg);padding:16px;border-radius:10px;margin:12px 0;font-family:monospace;font-size:16px"> PSCC = Uo / (R1 + Rn) </div> <p>This is used to verify protective devices at distribution boards and sub-boards.</p> <h2>Why PFC matters on site</h2> <ul> <li>A device with too low a breaking capacity may not interrupt the fault current</li> <li>This can cause arcing, fire, and catastrophic failure of the protective device</li> <li>Always check device Icc rating against calculated PFC</li> </ul> <h2>Key exam points</h2> <ul> <li>PFC = Uo / Ze where Uo = 230V</li> <li>PFC at Ze = 0.35Ω: 230 / 0.35 = 657A</li> <li>PFC at Ze = 0.20Ω: 230 / 0.20 = 1150A</li> <li>Standard MCBs rated 6kA — adequate for all domestic supplies</li> <li>Record PFC on schedule of test results</li> </ul>